If $f$ is defined by $f(x)=\left\{\begin{array}{cc}\frac{1-\cos a x}{x \sin x}, $(x
eq 0)$ \frac{1}{2} \quad,(x=0)\end{array} ight.$ and $f$ is continuous at $x=0$, then $a^2=$

Question

If $f$ is defined by $f(x)=\left\{\begin{array}{cc}\frac{1-\cos a x}{x \sin x}, $(x 
eq 0)$ \frac{1}{2} \quad,(x=0)\end{array}ight.$ and $f$ is continuous at $x=0$, then $a^2=$

Aicharya · Accepted Answer

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If $f$ is defined by $f(x)=\left\{\begin{array}{cc}\frac{1-\cos a x}{x \sin x}, $(x \neq 0)$ \frac{1}{2}…

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