If $\omega_1$ is angular velocity of hour hand of clock and $\omega_2$ is angular velocity of the earth,…

If $\omega_1$ is angular velocity of hour hand of clock and $\omega_2$ is angular velocity of the earth, then the ratio $\omega_1: \omega_2$ is
  1. $1: 2$
  2. $2: 3$
  3. $3: 2$
  4. $2: 1$

Solution

$\frac{\omega_1}{\omega_2}=\frac{\mathrm{T}_2}{\mathrm{~T}_1}=\frac{24 \text { hours }}{12 \text { hours }}=2$

Asked in: MHT CET 2021 (22 Sep Shift 1)

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