If $p: 25$ is an odd prime number. $q: 14$ is a composite number and $r: 64$ is a perfect square number.…
If $p: 25$ is an odd prime number.
$q: 14$ is a composite number and
$r: 64$ is a perfect square number.
Then which of the following statement pattern is true?
$\sim(q \wedge r) \vee p$
$(p \wedge q) \vee r$
$(p \vee q) \wedge(\sim r)$
$\sim p \vee(q \wedge r)$
Solution
Here, $P \equiv \mathrm{F}, q \equiv \mathrm{T}, r \equiv \mathrm{T}$
$\Rightarrow \sim p \vee(q \wedge r)$ is true