If $n$ is an integer with $0 \leq n \leq 11$, then the minimum value of $n !(11-1)$ ! is attained when a value of $n$ equals to

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Aicharya · Accepted Answer

We know, ${ }^{11} C_n$ is maximum when $n=5$. $ 	herefore{ }^{11} C_n=\frac{11 !}{n !(11-n) !} $ $	herefore n !(11-n) !$ is minimum when $n=5$

If $n$ is an integer with $0 \leq n \leq 11$, then the minimum value of $n !(11-1)$ ! is attained when a…