If $A=\left[\begin{array}{ccc}x & 1 & 2 \\ 2 & 4 & x \\ -3 & 3 & 2\end{array}\right]$ is a singular matrix…

If $A=\left[\begin{array}{ccc}x & 1 & 2 \\ 2 & 4 & x \\ -3 & 3 & 2\end{array}\right]$ is a singular matrix and the distinct values of $x$ are $x_1$ and $x_2$, then $x_1+x_2+x_1 x_2=$.
  1. -9
  2. $11 / 3$
  3. $15 / 3$
  4. 7

Solution

Given, $A=\left[\begin{array}{ccc}x & 1 & 2 \\ 2 & 4 & x \\ -3 & 3 & 2\end{array}\right]$ is singular, when $ \begin{aligned} & \left|\begin{array}{lll} A \mid=0 \\ x & 1 & 2 \\ 2 & 4 & x \\ -3 & 3 & 2 \end{array}\right|=0 \\ & \Rightarrow \quad x(8-3 x)-1(4+3 x)+2(6+12)=0 \\ & \Rightarrow \quad 8 x-3 x^2-4-3 x+36=0 \\ & \Rightarrow \quad \quad 3 x^2-5 x-32=0 \\ & \therefore x_1+x_2=\frac{5}{3} \text { and } x_1 x_2=-\frac{32}{3} \\ & x_1+x_2+x_1 x_2=\frac{5}{3}-\frac{32}{3}=-\frac{27}{3}=-9 \end{aligned} $

Asked in: AP EAMCET 2022 (06 Jul Shift 2)

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