If $(3+i)$ is a root of $x^2+a x+b=0$ then $a=$

If $(3+i)$ is a root of $x^2+a x+b=0$ then $a=$
  1. 3
  2. -3
  3. 6
  4. -6

Solution

Roots of equation are $(3+i)$ and $(3-i)$
Sum of roots $=-a=6 \Rightarrow a=-6$

Asked in: AP EAMCET 2024 (21 May Shift 1)

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