If $\mathrm{X}$ is a random variable with the following probability distribution $\begin{array}{|l|c|c|c|}…

If $\mathrm{X}$ is a random variable with the following probability distribution $\begin{array}{|l|c|c|c|} \hline \mathrm{X}=x & -3 & 6 & 9 \\ \hline \mathrm{P}(\mathrm{X}=x) & \frac{1}{6} & \frac{1}{2} & \frac{1}{3} \\ \hline \end{array}$ then the variance of $\mathrm{X}$ is
  1. $\frac{65}{4}$
  2. $\frac{65}{2}$
  3. $\frac{65}{3}$
  4. 65

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 1)

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