If $M$ is a point on the line $y=x$ and points $P(0,1), Q(2,0)$ are such that $P M+Q M$ is minimum, the…

If $M$ is a point on the line $y=x$ and points $P(0,1), Q(2,0)$ are such that $P M+Q M$ is minimum, the coordinates of $M$ are
  1. $(0,0)$
  2. $\left(\frac{13}{17}, \frac{13}{17}\right)$
  3. $\left(\frac{2}{3}, \frac{2}{3}\right)$
  4. $\left(\frac{31}{7}, \frac{31}{7}\right)$

Solution

Given, $ \begin{aligned} & P=(0,1) \\ & Q=(2,0) \end{aligned} $ Let $\quad M=(a, a) \quad[\because M$ lies on the line $y=x]$ In order to Make $P M+Q M$ is minimum $\Rightarrow P, M, Q$ Must be collinear $\therefore$ Slope of $P M=$ Slope of $Q M$ $ \begin{aligned} & \frac{a-1}{a-0}=\frac{a-0}{a-2} \\ &(a-1)(a-2)=a^2 \\ & a^2-3 a+2=a^2 \\ &-3 a=-2 \\ & a=\frac{2}{3} \\ & \therefore M \text { is }\left(\frac{2}{3}, \frac{2}{3}\right) \end{aligned} $

Asked in: AP EAMCET 2020 (22 Sep Shift 2)

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