If $\alpha$ is a non-real root of the equation $x^6-1=0$ then…
If $\alpha$ is a non-real root of the equation $x^6-1=0$ then $\frac{\alpha^2+\alpha^3+\alpha^4+\alpha^5}{\alpha+1}=$
- $\alpha$
- 1
- 0
- $-1$
Solution
No solution. Refer to answer key.
Asked in: AP EAMCET 2017 (25 Apr Shift 1)
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