If $Z$ is a complex number such that $|Z| \leq 3$ and $\frac{-\pi}{2} \leq a m p Z \leq \frac{\pi}{2}$, then…
- $9 \pi$
- $\frac{9 \pi}{2}$
- $3 \pi$
- $\frac{9 \pi}{4}$
Solution

$|Z| \leq 3$, $-\frac{\pi}{2} \leq \operatorname{amp}(Z) \leq \frac{\pi}{2}$
Required region is semicircle with radius 3. $\text { Required area }=\frac{\pi \times 3^2}{2}=\frac{9 \pi}{2} .$
Asked in: AP EAMCET 2024 (22 May Shift 1)