If $\omega$ is a complex cube root of unity and $a, b, c$ are distinct real numbers, then $ \frac{a+b…

If $\omega$ is a complex cube root of unity and $a, b, c$ are distinct real numbers, then $ \frac{a+b \omega+c \omega^2}{c+a \omega+b \omega^2}+\frac{a+b \omega+c \omega^2}{b+c \omega+a \omega^2}= $
  1. 1
  2. -1
  3. $a+b+c$
  4. 0

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2018 (24 Apr Shift 2)

Practice more Complex Number questions on Aicharya