Mathematics › Definite Integration › Definite Integration by Parts
In=∫π/4π/2cotnxdx=∫π/4π/2cotn-2xcosec2x-1dx
=-cotn-1xn-1π/4π/2-In-2
=1n-1-In-2
⇒In+In-2=1n-1
⇒I2+I4=13
I3+I5=14
I4+I6=15
∴1I2+I4,1I3+I5,1I4+I6 are in A.P.
Asked in: JEE Main 2021 (25 Feb Shift 2)
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