If in the circuit, power dissipation is $150 \mathrm{~W}$, then $\mathrm{R}$ is

If in the circuit, power dissipation is $150 \mathrm{~W}$, then $\mathrm{R}$ is
  1. $2 \Omega$
  2. $6 \Omega$
  3. $5 \Omega$
  4. $4 \Omega$

Solution

$W=\frac{V^2}{R_{\text {net }}} ; 150=\frac{(15)^2}{R}+\frac{(15)^2}{2} \Rightarrow R=6 \Omega$

Asked in: JEE Main 2002

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