If in a hyperbola, the distance between the foci is 10 and transverse axis has length 8, then the length of…
If in a hyperbola, the distance between the foci is 10 and transverse axis has length 8, then the length of its latus rectum is
- 9
- $\frac{9}{2}$
- $\frac{32}{3}$
- $\frac{64}{3}$
Solution
Given,
$
2 a e=10 \text { and } 2 a=8
$
$
a e=5, a=4
$
In hyperbola,
$
\begin{aligned}
& & (a e)^2 & =a^2+b^2 \\
\Rightarrow & & 25 & =16+b^2 \\
\Rightarrow & & b^2 & =9
\end{aligned}
$
Length of latus rectum $=\frac{2 b^2}{a}=\frac{2 \times 9}{4}=\frac{9}{2}$
Asked in: AP EAMCET 2021 (25 Aug Shift 1)
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