If $(p \wedge \sim r) \rightarrow(\sim p \vee q)$ has truth value False, then truth values of $p, q, r$ are respectively.

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Aicharya · Accepted Answer

Given that $\begin{array}{ll} & (p \wedge \sim r) \rightarrow(\sim p \vee q) \equiv F \ \therefore & \sim p \vee q \equiv F \ \therefore & \sim p \equiv F \text { and } q \equiv F \ \therefore & p=T \text { and } q=F \ \therefore & \text { Option }(C) \text { is correct. } \end{array}$

If $(p \wedge \sim r) \rightarrow(\sim p \vee q)$ has truth value False, then truth values of $p, q, r$ are…

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