Mathematics › Indefinite Integration › Integration by Substitution
fx=∫5x8+7x6dxx14x-5+x-7+22
Let x-5+x-7+2=t
-5x-6-7x-8dx=dt
⇒fx=∫-dtt2=1t+c
fx=x7x2+1+2x7
f1=14
Asked in: JEE Main 2021 (18 Mar Shift 1)
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