If f : R → R is given by f ( x ) = x + 1 , then the value of lim n → ∞ 1 n f 0 + f 5 n + f…

If f:RR is given by f(x)=x+1, then the value of limn1nf0+f5n+f10n+..+f5(n-1)n is:
  1. 32
  2. 52
  3. 12
  4. 72

Solution

Let

I=limn1nf0+f5n+f10n+..+f5(n-1)n

I=r=0n-1f5rn1n

I=01f5xdx

I=015x+1dx

I=5x22+x01

I=52+1=72

Asked in: JEE Main 2021 (20 Jul Shift 2)

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