If f : R → R is a twice differentiable function such that f ′ ′ x > 0 for all x &#8712…

If f:RR is a twice differentiable function such that fx>0 for all xR and f12=12, f1=1 then
  1. 0<f112
  2. f10
  3. f1>1
  4. 12<f11

Solution

Using LMVT on  fx for x12, 1

f1-f121-12=f'c, where c12, 1

1-1212=f'c    f'c=1, where c12, 1

f  ″ x > 0 x R
 

     f'x is an increasing function  xR

f  ′ 1 > 1

Asked in: JEE Advanced 2017 (Paper 2)

Practice more Hyperbola questions on Aicharya