If four different elements $\mathrm{A}, \mathrm{B}, \mathrm{C}$ and D having electronic configuration as $A=[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^4$, $\dot{B}=[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^5, \mathrm{C}=[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^4$ and…

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If four different elements $\mathrm{A}, \mathrm{B}, \mathrm{C}$ and D having electronic configuration as $A=[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^4$, $\dot{B}=[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^5, \mathrm{C}=[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^4$ and $\mathrm{D}=[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^2 4 \mathrm{p}^5$. Identify the element with largest atomic radius.

Aicharya · Accepted Answer

Elements C and D belong to period 4 , while elements A and B are from period 3, therefore the former will be larger in size. The configuration of $C$ and $D$ is $4 \mathrm{~s}^2 4 \mathrm{p}^4$ and $4 \mathrm{~s}^2 4 \mathrm{p}^5$ respectively, therefore D lies to the right of C and would be smaller than C . $	herefore \quad$ Element C will have the largest atomic radius.

If four different elements $\mathrm{A}, \mathrm{B}, \mathrm{C}$ and D having electronic configuration as…

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