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A=1-ααβ AAT=I2
⇒1-ααβ1α-αβ=1001
⇒1+α2α-αβα-αβα2+β2=1001
⇒1+α2=1 & α2+β2=1
⇒α2=0 & β2=1
∴ α4=0 & β4=1
∴ α4+β4=1
Asked in: JEE Main 2021 (25 Feb Shift 2)
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