If for some α and β in R , the intersection of the following three planes x + 4 y - 2 z = 1 x + 7…

If for some α and β in R , the intersection of the following three planes
x+4y-2z=1
x+7y-5z=β
x+5y+αz=5
is a line in R3 , then α+β is equal to:
  1. 0
  2. 10
  3. 2
  4. -10

Solution

=014-217-515α=0
7α+25-4α+10+-20+14=0
3α+9=0α=-3
Also Dz=014117β155=0
135-5β-15+14β-7=0
β=13

Asked in: JEE Main 2020 (09 Jan Shift 1)

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