Mathematics › Functions › Functional Equation
Given:fx=x2+ax+b⇒f0=bSo,ff0=fb=0⇒b2+ab+b=0⇒bb+a+1=0⇒b+a+1=0∵b≠0⇒a+b=-1
Given:
fx=x2+ax+b
⇒f0=b
So,
ff0=fb=0
⇒b2+ab+b=0
⇒bb+a+1=0
⇒b+a+1=0
∵b≠0
⇒a+b=-1
Asked in: AP EAMCET 2022 (04 Jul Shift 2)
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