If f ' ( x ) = x + 1 x , then f ( x ) =

If f'(x)=x+1x, then f(x)=
  1. x2+log(x)+c
  2. x22+logx+c
  3. x+log(x)+c
  4. x2+log(x)+c

Solution

f'x=x+1x

integrating both sides

∫f'(x)dx=∫x+1xdx

∫f'(x)dx=∫xdx+∫1xdx

⇒fx=x22+logx+C

Asked in: AP EAMCET 2021 (20 Aug Shift 2)

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