If f ( 10 - x ) = 3 x 2 + 4 x - 5 and f ( x ) = p x 2 + q x + r then p + q + r =

If f(10-x)=3x2+4x-5 and f(x)=px2+qx+r then p+q+r=
  1. 272
  2. 274
  3. 275
  4. 273

Solution

Given: f10-x=3x2+4x-5

fx=px2+qx+r

p+q+r=f1

p+q+r=f10-9

⇒ p+q+r=3×92+4×9-5

⇒ p+q+r=243+36-5

⇒ p+q+r=274

Asked in: AP EAMCET 2021 (20 Aug Shift 2)

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