If eight coins are tossed simultaneously, then the probability of getting atleast six heads is
If eight coins are tossed simultaneously, then the probability of getting atleast six heads is
$\frac{37}{64}$
$\frac{37}{512}$
$\frac{37}{256}$
$\frac{37}{128}$
Solution
Since 8 coins are tossed simultaneously. Hence total samples $=2^8=256=n(\mathrm{~S})$ Number of ways of getting at least 6 heads $={ }^8 c_6+{ }^8 c_7+{ }^8 c_8=37=n(\mathrm{E})$
Therefore,
Required probability $=\frac{n(\mathrm{E})}{n(\mathrm{~S})}=\frac{37}{256}$