If $z=3+5 i$, then $z^3+\bar{z}+198$ is equal to
If $z=3+5 i$, then $z^3+\bar{z}+198$ is equal to
- $-3-5 i$
- $-3+5 i$
- $3-5 i$
- $3+5 i$
Solution
We have,
$
\begin{aligned}
z & =3+5 i \\
\therefore \quad \bar{z} & =3-5 i \\
z^3 & =z^2 \cdot z=(3+5 i)^2(3+5 i) \\
& =(9-25+30 i)(3+5 i) \\
& =(-16+30 i)(3+5 i) \\
& =-48-150+10 i \\
& =-198+10 i
\end{aligned}
$
Now,
$
\begin{aligned}
z^3+\bar{z}+198 & =-198+10 \dot{i}+3-5 i+198 \\
& =3+5 i
\end{aligned}
$
Asked in: AP EAMCET 2002
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