If $z=3+5 i$, then $z^3+\bar{z}+198$ is equal to

If $z=3+5 i$, then $z^3+\bar{z}+198$ is equal to
  1. $-3-5 i$
  2. $-3+5 i$
  3. $3-5 i$
  4. $3+5 i$

Solution

We have, $ \begin{aligned} z & =3+5 i \\ \therefore \quad \bar{z} & =3-5 i \\ z^3 & =z^2 \cdot z=(3+5 i)^2(3+5 i) \\ & =(9-25+30 i)(3+5 i) \\ & =(-16+30 i)(3+5 i) \\ & =-48-150+10 i \\ & =-198+10 i \end{aligned} $ Now, $ \begin{aligned} z^3+\bar{z}+198 & =-198+10 \dot{i}+3-5 i+198 \\ & =3+5 i \end{aligned} $

Asked in: AP EAMCET 2002

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