If $y=e^{\sin \left(\operatorname{cosec}^{-1} x\right)}$ , then $\frac{d y}{d x}=$

If $y=e^{\sin \left(\operatorname{cosec}^{-1} x\right)}$ , then $\frac{d y}{d x}=$
  1. $\frac{e^{\frac{1}{x}}}{x^{2}}$
  2. $-\frac{e^{\frac{1}{x}}}{x^{2}}$
  3. 0
  4. $e^{\cos \left(\operatorname{cosec}^{-1} x\right)}$

Solution

Given $y=e^{\sin \left(\operatorname{cosec}^{-1} x\right)}$ $\quad=e^{\sin \left(\sin ^{-1} \frac{1}{x}\right)} \Rightarrow y=e^{\frac{1}{x}}$ $\frac{d y}{d x}=e^{\frac{1}{x}}\left(-\frac{1}{x^{2}}\right)$

Asked in: MHT CET 2020 (14 Oct Shift 2)

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