If $x=e^{\left(\frac{x}{y}\right)}$, then $\frac{d y}{d x}=$
If $x=e^{\left(\frac{x}{y}\right)}$, then $\frac{d y}{d x}=$
- $\frac{x-y}{x \log y}$
- $\frac{x-y}{y \log x}$
- $\frac{x-y}{x \log x}$
- $\frac{x+y}{x \log x}$
Solution
$x=e^{\left(\frac{x}{y}\right)} \Rightarrow \log _e x=\frac{x}{y} \Rightarrow y \log _e x=x$
Differentiating both sides w.r.t $x$ we get $\frac{d y}{d x} \cdot \log _e x+y \cdot \frac{1}{x}=1$
$\Rightarrow \frac{d y}{d x} \cdot x \log _e x+y=x$
$\Rightarrow \frac{d y}{d x}=\frac{x-y}{x \log _e x}$
Change the option (C) as $\frac{x-y}{x \log x}$
Asked in: MHT CET 2022 (05 Aug Shift 2)
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