If $\sqrt{a^{2} + b^{2}} = c$ and $a = 8$, $b = 15$, then $c$ equals

If $\sqrt{a^{2} + b^{2}} = c$ and $a = 8$, $b = 15$, then $c$ equals
  1. $17$
  2. $23$
  3. $15$
  4. $16$

Solution

$c = \sqrt{64 + 225} = \sqrt{289} = 17$.

Asked in: IMO

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