If $\sin \left(5 x+\frac{\pi}{4}\right)=0$, then $x$ is equal to

If $\sin \left(5 x+\frac{\pi}{4}\right)=0$, then $x$ is equal to
  1. $\frac{-\pi}{20}+\frac{\pi}{2} n(n \in z)$
  2. $\frac{\pi}{20}+\frac{\pi}{5} n(n \in z)$
  3. $\frac{-\pi}{5}+\frac{\pi}{5} n(n \in z)$
  4. $\frac{-\pi}{20}+\frac{\pi}{5} n(n \in z)$

Solution

$\sin \left(5 x+\frac{\pi}{4}\right)=0=\sin n \pi(\because \sin n \pi=0)$ where $n \in Z$ $ \begin{array}{rlrl} \Rightarrow & & 5 x+\frac{\pi}{4} & =n \pi \\ \Rightarrow & x & =\frac{1}{5}\left(n \pi-\frac{\pi}{4}\right)=\frac{n \pi}{5}-\frac{\pi}{20} \end{array} $

Asked in: AP EAMCET 2021 (23 Aug Shift 1)

Practice more Trigonometric Ratios & Identities questions on Aicharya