If $\sin \left(5 x+\frac{\pi}{4}\right)=0$, then $x$ is equal to
If $\sin \left(5 x+\frac{\pi}{4}\right)=0$, then $x$ is equal to
- $\frac{-\pi}{20}+\frac{\pi}{2} n(n \in z)$
- $\frac{\pi}{20}+\frac{\pi}{5} n(n \in z)$
- $\frac{-\pi}{5}+\frac{\pi}{5} n(n \in z)$
- $\frac{-\pi}{20}+\frac{\pi}{5} n(n \in z)$
Solution
$\sin \left(5 x+\frac{\pi}{4}\right)=0=\sin n \pi(\because \sin n \pi=0)$ where $n \in Z$
$
\begin{array}{rlrl}
\Rightarrow & & 5 x+\frac{\pi}{4} & =n \pi \\
\Rightarrow & x & =\frac{1}{5}\left(n \pi-\frac{\pi}{4}\right)=\frac{n \pi}{5}-\frac{\pi}{20}
\end{array}
$
Asked in: AP EAMCET 2021 (23 Aug Shift 1)
Practice more Trigonometric Ratios & Identities questions on Aicharya