If $\quad f: R \rightarrow R \quad$ is defined by $f(x)=[x-3]+|x-4|$ for $x \in R$, then $\lim _{x…
If $\quad f: R \rightarrow R \quad$ is defined by $f(x)=[x-3]+|x-4|$ for $x \in R$, then $\lim _{x \rightarrow 3^{-}} f(x)$ is equal to
- $-2$
- $-1$
- $0$
- $1$
Solution
Given that,
$
\begin{aligned}
f(x) & =[x-3]+|x-4| \\
\therefore \lim _{x \rightarrow 3^{-}} f(x) & =\lim _{x \rightarrow 3^{-}}([x-3]+|x-4|) \\
& =\lim _{h \rightarrow 0}([3-h-3]+|3-h-4|) \\
& =\lim _{h \rightarrow 0}([-h]+1+h) \\
& =-1+1+0=0
\end{aligned}
$
Asked in: AP EAMCET 2008
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