If $p(x) = x^{3} - 8$, then $p(2)$ is

If $p(x) = x^{3} - 8$, then $p(2)$ is
  1. $0$
  2. $8$
  3. $16$
  4. $-8$

Solution

$8 - 8 = 0$ — $2$ is a zero of $x^{3} - 8$.

Asked in: MH-SSC-9

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