If $p(x) = x^{2} + kx + 6$ has $(x - 2)$ as a factor, $k$ equals

If $p(x) = x^{2} + kx + 6$ has $(x - 2)$ as a factor, $k$ equals
  1. $-5$
  2. $5$
  3. $-3$
  4. $3$

Solution

$p(2) = 4 + 2k + 6 = 10 + 2k = 0 \Rightarrow k = -5$.

Asked in: MH-SSC-9

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