If $p(x) = x^{2} - 5x + 6$, zeros of $p(x)$ are
If $p(x) = x^{2} - 5x + 6$, zeros of $p(x)$ are
- $2$ and $3$
- $1$ and $6$
- $-2$ and $-3$
- $5$ and $6$
Solution
$x^{2} - 5x + 6 = (x-2)(x-3)$. Zeros: $x = 2, 3$.
Asked in: MH-SSC-9
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