If $p(x) = x^{2} - 4x + 4$, $p(2)$ equals

If $p(x) = x^{2} - 4x + 4$, $p(2)$ equals
  1. $0$
  2. $4$
  3. $-4$
  4. $8$

Solution

$(x-2)^{2}$ at $x=2$ is $0$.

Asked in: MH-SSC-9

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