If $p(x) = ax^{3} + 3x^{2} - 13$ and the remainder when divided by $(x - 2)$ is $7$, then $a$ equals
If $p(x) = ax^{3} + 3x^{2} - 13$ and the remainder when divided by $(x - 2)$ is $7$, then $a$ equals
- $1$
- $2$
- $-1$
- $0$
Solution
$p(2) = 8a + 12 - 13 = 8a - 1 = 7 \Rightarrow 8a = 8 \Rightarrow a = 1$.
Asked in: MH-SSC-9
Practice more Polynomials questions on Aicharya