If $p$ and $q$ are the roots of the equation $x^2+p x+q=0$, then

If $p$ and $q$ are the roots of the equation $x^2+p x+q=0$, then
  1. p =1, q = -2
  2. p = 0, q = 1
  3. p = -2, q = 0
  4. p = -2, q = 1

Solution

$p+q=-p$ and $p q=q \Rightarrow q(p-1)=0 \Rightarrow q=0$ or $p=1$ If $q=0$, then $p=0$. i.e. $p=q \quad \therefore p=1$ and $q=-2$

Asked in: JEE Main 2002

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