If $p$ and $q$ are the roots of the equation $x^2+p x+q=0$, then
If $p$ and $q$ are the roots of the equation $x^2+p x+q=0$, then
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p =1, q = -2
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p = 0, q = 1
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p = -2, q = 0
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p = -2, q = 1
Solution
$p+q=-p$ and $p q=q \Rightarrow q(p-1)=0 \Rightarrow q=0$ or $p=1$
If $q=0$, then $p=0$. i.e. $p=q \quad \therefore p=1$ and $q=-2$
Asked in: JEE Main 2002
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