If $p \rightarrow(\sim p \vee q)$ is false, then the truth values of $p$ and $q$ are, respectively
If $p \rightarrow(\sim p \vee q)$ is false, then the truth values of $p$ and $q$ are, respectively
- T, F
- F, F
- F, T
- T, T
Solution
$\mathrm{p} \rightarrow(\sim \mathrm{p} \vee \mathrm{q}) \equiv \mathrm{F}$
We know that $\mathrm{T} \rightarrow \mathrm{F} \equiv \mathrm{F}$
$\therefore \mathrm{p} \equiv \mathrm{T} \text { and }(\sim \mathrm{p} \vee 1) \equiv \mathrm{F}$
We know that $\mathrm{F} \vee \mathrm{F} \equiv \mathrm{F}$
$\therefore \sim \mathrm{p} \equiv \mathrm{F} \text { and } \mathrm{q} \equiv \mathrm{F}$
Thus p, q are T, F respectively.
Asked in: MHT CET 2021 (21 Sep Shift 2)
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