If $n(A) = 5$, $n(B) = 7$ and $n(A \cap B) = 3$, then $n(A \cup B)$ equals
If $n(A) = 5$, $n(B) = 7$ and $n(A \cap B) = 3$, then $n(A \cup B)$ equals
- $9$
- $12$
- $15$
- $10$
Solution
$n(A \cup B) = n(A) + n(B) - n(A \cap B) = 5 + 7 - 3 = 9$.
Asked in: MH-SSC-9
Practice more Sets questions on Aicharya