If $n(A) = 12$, $n(B) = 8$, and $A$ and $B$ are disjoint, then $n(A \cup B)$ is

If $n(A) = 12$, $n(B) = 8$, and $A$ and $B$ are disjoint, then $n(A \cup B)$ is
  1. $20$
  2. $0$
  3. $4$
  4. $16$

Solution

For disjoint sets $n(A \cap B) = 0$, so $n(A \cup B) = 12 + 8 = 20$.

Asked in: MH-SSC-9

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