If $\mathrm{A}=\left[\begin{array}{cc}2 & -2 \ 4 & 3\end{array} ight]$, then $\mathrm{A}^{-1}=$

Question

If $\mathrm{A}=\left[\begin{array}{cc}2 & -2 \ 4 & 3\end{array}ight]$, then $\mathrm{A}^{-1}=$

Aicharya · Accepted Answer

$\begin{aligned} A & =\left[\begin{array}{cc}2 & -2 \ 4 & 3\end{array}ight] \ & A^{-1}=\frac{1}{|A|} \operatorname{Adj} A \ 	herefore \quad A^{-1} & =\frac{1}{14}\left[\begin{array}{cc}3 & 2 \ -4 & 2\end{array}ight]\end{aligned}$

If $\mathrm{A}=\left[\begin{array}{cc}2 & -2 \\ 4 & 3\end{array}\right]$, then $\mathrm{A}^{-1}=$

Solution