If $\lim _{x \rightarrow 1} \frac{x^2-a x+b}{(x-1)}=5$, then $(a+b)$ is equal to

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Aicharya · Accepted Answer

Applying $\Rightarrow a=-3$ Hospital's rule $\begin{aligned} & \Rightarrow 2 	imes 1-a=5 \ & \Rightarrow a=-3\end{aligned}$ from (1) $b=-4$ $\Rightarrow a+b=-7$

If $\lim _{x \rightarrow 1} \frac{x^2-a x+b}{(x-1)}=5$, then $(a+b)$ is equal to

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