If $\left[\begin{array}{ccc}1 & 1 & 1 \ 1 & -2 & -2 \ 1 & 3 & 1\end{array} ight]\left[\begin{array}{l}x \ y \ z\end{array} ight]=\left[\begin{array}{l}0 \ 3 \ 4\end{array} ight]$, then $2 x-y+z=$

Question

If $\left[\begin{array}{ccc}1 & 1 & 1 \ 1 & -2 & -2 \ 1 & 3 & 1\end{array}ight]\left[\begin{array}{l}x \ y \ z\end{array}ight]=\left[\begin{array}{l}0 \ 3 \ 4\end{array}ight]$, then $2 x-y+z=$

Aicharya · Accepted Answer

From the given equation we have Solving we get $x=1, y=2$ and $z=-3$ Now, $2 x-y+z=2 	imes 1-2+(-3)=-3$

If $\left[\begin{array}{ccc}1 & 1 & 1 \\ 1 & -2 & -2 \\ 1 & 3 & 1\end{array}\right]\left[\begin{array}{l}x…

Solution