If $\int_{0}^{1}\left(5 x^{2}-3 x+k\right) d x=0$, then $k=$

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Aicharya · Accepted Answer

Given $\int_{0}^{1}\left(5 x^{2}-3 x+kight) d x=0$ $	herefore\left[5 \frac{x^{3}}{3}-\frac{3 x^{2}}{2}+k xight]_{0}^{1}=0 \Rightarrow \frac{5}{3}-\frac{3}{2}+k=0 \Rightarrow k=-\frac{1}{6}$

If $\int_{0}^{1}\left(5 x^{2}-3 x+k\right) d x=0$, then $k=$

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