If $\int \frac{2 x^{2}+3}{\left(x^{2}-1\right)\left(x^{2}+4\right)} d x=a \log…

If $\int \frac{2 x^{2}+3}{\left(x^{2}-1\right)\left(x^{2}+4\right)} d x=a \log \left|\frac{x-1}{x+1}\right|+b \tan ^{-1}\left(\frac{x}{2}\right)+C$, then
  1. $\mathrm{a}=\frac{1}{2}, \quad \mathrm{~b}=\frac{1}{2}$
  2. $\mathrm{a}=-1, \mathrm{~b}=1$
  3. $\mathrm{a}=\frac{1}{2}, \quad \mathrm{~b}=\frac{-1}{2}$
  4. $\mathrm{a}=1, \quad \mathrm{~b}=-1$

Solution

$\begin{aligned} \text {Let } I &=\int \frac{2 x^{2}+3}{\left(x^{2}-1\right)\left(x^{2}+4\right)} d x=\int\left[\frac{1}{x^{2}-1}+\frac{1}{x^{2}+4}\right] d x \\ I &=\frac{1}{2(1)} \log \left|\frac{x-1}{x+1}\right|+\frac{1}{2} \tan ^{-1} \frac{x}{2}+C \end{aligned}$ Comparing with given data, we get $a=\frac{1}{2}, b=\frac{1}{2}$

Asked in: MHT CET 2020 (20 Oct Shift 1)

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