If $h(x)=\sqrt{4 f(x)+3 g(x)}, f(1)=4, g(1)=3, f^{\prime}(1)=4$, then $\mathrm{h}^{\prime}(1)=$

If $h(x)=\sqrt{4 f(x)+3 g(x)}, f(1)=4, g(1)=3, f^{\prime}(1)=4$, then $\mathrm{h}^{\prime}(1)=$
  1. $\frac{5}{12}$
  2. $\frac{12}{5}$
  3. $\frac{-5}{12}$
  4. $\frac{-12}{7}$

Asked in: MHT CET 2021 (20 Sep Shift 1)

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