If $f(x)=b \cdot e^{a x}+a \cdot e^{b x}$, then $f^{\prime \prime}(0)=$

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Aicharya · Accepted Answer

$\begin{aligned} & f(x)=b \cdot e^{a x}+a \cdot e^{b x} \ & \Rightarrow f^{\prime}(x)=b a e^{a x}+a b e^{b x} \ & \Rightarrow f^{\prime \prime}(x)=b a^2 e^{a x}+a b^2 e^{b x} \ & \Rightarrow f^{\prime \prime}(0)=b a^2+a b^2=a b(a+b)\end{aligned}$

If $f(x)=b \cdot e^{a x}+a \cdot e^{b x}$, then $f^{\prime \prime}(0)=$

Solution