If $\dfrac{x}{2} = \dfrac{y}{3} = \dfrac{z}{4}$, then $x + y + z$ in terms of $z$ is

If $\dfrac{x}{2} = \dfrac{y}{3} = \dfrac{z}{4}$, then $x + y + z$ in terms of $z$ is
  1. $\dfrac{9z}{4}$
  2. $\dfrac{z}{9}$
  3. $3z$
  4. $z$

Solution

Let $\dfrac{z}{4} = k$, so $z = 4k$, $y = 3k$, $x = 2k$. Sum $= 9k = 9 \cdot \dfrac{z}{4}$.

Asked in: MH-SSC-9

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