If $A=\left[\begin{array}{lll}1 & 2 & 3 \ 1 & 3 & 4 \ 3 & 4 & 3\end{array} ight]$, then $A^{-1}=$

Question

If $A=\left[\begin{array}{lll}1 & 2 & 3 \ 1 & 3 & 4 \ 3 & 4 & 3\end{array}ight]$, then $A^{-1}=$

Aicharya · Accepted Answer

$\because A^{-1}=\frac{\operatorname{adj}(A)}{|A|}=-\frac{1}{4}\left[\begin{array}{ccc}-7 & 6 & -1 \ 9 & -6 & -1 \ -5 & 2 & 1\end{array}ight]$

If $A=\left[\begin{array}{lll}1 & 2 & 3 \\ 1 & 3 & 4 \\ 3 & 4 & 3\end{array}\right]$, then $A^{-1}=$