If $A=\left[\begin{array}{ll}3 & 2 \ 0 & 1\end{array} ight]$, then $\left(A^{-1} ight)^3=$

Question

If $A=\left[\begin{array}{ll}3 & 2 \ 0 & 1\end{array}ight]$, then $\left(A^{-1}ight)^3=$

Aicharya · Accepted Answer

$\left(A^{-1}ight)^3=\left(A^3ight)^{-1}=\left\{\left[\begin{array}{ll}3 & 2 \ 0 & 1\end{array}ight]^3ight\}^{-1}=\left[\begin{array}{cc}27 & 26 \ 0 & 1\end{array}ight]^{-1}=\frac{1}{27}\left[\begin{array}{cc}1 & -26 \ 0 & 27\end{array}ight]$

If $A=\left[\begin{array}{ll}3 & 2 \\ 0 & 1\end{array}\right]$, then $\left(A^{-1}\right)^3=$

Solution